Qualcomm Interview Question
Memory - 4byte accessible --- constraint randomize and select one random memory address
Interview Answer
Anonymous
Feb 28, 2021
bit [31:0] mem_start_addr, mem_end_addr; rand bit [31:0] start_addr, end_addr; rand int block_siz; constraint c { start_addr >= mem_start_addr; start_addr < mem_end_addr; end_addr == start_addr + block_siz -1; start_addr %4 ==0;};