Robert, solution is totally wrong) you are counting spaces not the words)

He's not really wrong. In the case of an empty string the length of the string will be 0. The moment you add a character we assume it's a word. With this in mind there are a couple of assumptions to be made: 1.) assuming you're not asking to check if the word is actually an {insert language here} word. 2.) we're assuming there is an equal amount of spaces between each word. 3.) there is no extra space at the end of the sentence. The moment you begin counting pass 1 you know that there will be n + 1 words where n is the numbers of spaces. If these assumptions were made by Robert, he isn't exactly wrong to count spaces.

In java, I would use the split method, is that not allowed? And store into a string array, then get size of array.

- (int)numberOfWordsInString:(NSString *)phrase { int numberOfWords = 0; for(int i = 0; i < phrase.stringLength.count; i++) { char *currentLetter = phrase[i]; if ([char isEqualToString:@" "]){ numberOfWords++; } } return numberOfWords; } *this is not a real programming language this is just how i would do it in my head