Given two integers dividend and divisor, divide two integers without using multiplication, division and mod operator.

Question

Anonymous · Accepted Answer

Both dividend and divisor will be 32-bit signed integers.
The divisor will never be 0.
Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231,  231 − 1]. For the purpose of this problem, assume that your function returns 231 − 1 when the division result overflows

Interview Answer · Answer

You could make a loop with the condition of (dividend >= divisor), and while that is true, continue to subtract dividend from the divisor and assign the dividend to this difference. 

while (dividend >= divisor) { 
(dividend = dividend - divisor);
quotient++;
}

This loop will also add one to our quotient through each pass (quotient++). If our Dividend was 26 and our divisor was 8, this loop would run 3 times (quotient++ would be reached three times). This would mean our answer, our final quotient, is 3.

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