How do you make a function that takes f and returns a function that calls f on a timeout?

Question

Anonymous · Accepted Answer

function delay(f, duration) {
	return (...args) => {
		setTimeout[() => {
			f(...args);
		}, duration);
	}
}

joe · Answer

function callOnTimeout(f){
	const fcnToReturn = function (to){
  	    setTimeout[f, to)
        }
       return fcnToReturn
}

const f = function (){
	console.log ('i got called')
}

const myTimeoutFcn = callOnTimeout(f)

myTimeoutFcn(2000)

a guy · Answer

function foo(f){
      return (function() {
        setTimeout[function() {f();}, 0);
      })();
    }

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