Optiver Interview Question
Prob(50 Heads in 100 Tosses)
Interview Answer
Anonymous
May 6, 2024
B(100, 0.5) ~ N(50, sigma = 5) answer ~ Prob(49.5 < Z < 50.5) = +- 0.1 sd from mean in normal diet = 0.08
Prob(50 Heads in 100 Tosses)
Anonymous
B(100, 0.5) ~ N(50, sigma = 5) answer ~ Prob(49.5 < Z < 50.5) = +- 0.1 sd from mean in normal diet = 0.08
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