Find the 'leftmost' node in a binary tree.
Anonymous
1. Start with the root node 2. Do in order search but without the right and root traversal 3. Node inorder(Node node) { if(node == null) { return null; } Node leftNode = inorder(node.left); if(leftNode== null) { return node } else { return leftNode; } } 4. print inorder(root);
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